The genome of E coli contains 4 million base pairs or 4×10^6 bp. The number of turns of DNA present is

[wp_quiz id=”14325″]

The genome of E coli contains 4 million base pairs or 4×10⁶ bp. The number of turns of DNA present is 400,000 turns or (4×10⁵) turns. In general, in the B form of DNA, one turn of DNA contains 10 bp. Therefore, the number of turns present in the genome is around 10 times less than the number of base pairs.

So, if the genome of E coli contains 4 million base pairs or 4×10⁶ bp, the number of turns of DNA present is about 10 times less or 400,000 turns or (4×10⁵) turns.